## Matlab Tutorial 3: Strings in Matlab

The concept of variables is fundamental in all programming. In Matlab you introduce variables and assign values to them all by yourself. When you assign a value to a variable its previously assigned value will be overwritten. You can at any time find out the actual value of a variable simply by writing the variable name in the command window (without ;).

The class is decided by the assigned value.

`>> a=1; % the class is double and the storage size is 8 bytes.`

Open and check workspace.

In this laboratory we will investigate strings and conversions of strings among other things. A string is stored as a row vector, so that every element represents a character. Each character is accessible by the name of the vector and its indice.

#### Exercise 1: Assigning a variable to a string of characters

`>> words='This is a string'`

Press on enter to see the content of the variable words. Words has the size 1×16 elements. The class is char (character) and storage size 32 bytes.

```>> words(2) % gives the second element in the variable words. ans = h```
`>> words(2)='t' % replaces the second element in the vector with t.`

Sooner or later we need some form of interactivity. For instance to get input from the user. To prompt the user for an input:

Pages: 1 2 3 4 5

1. Khashabi — May 19, 2010 @ 6:23 pm

great !
go on …

2. Khashabi — May 19, 2010 @ 7:20 pm

seems missing a ‘\’ before ‘n’ (new line escape character)
Line: x= input(‘Give me a name !: n’,’s’); % skips a row

3. saravanan — November 21, 2011 @ 9:52 am

You are saying it is possible to change a letter by assigning with new string. Is it possible in structures, for example,

s.text = ‘TITLE=”PhotoStudio Exported Data”‘
[1×98 char]
‘ZONE T=”PhotoStudio Data” K = 147 F=PAINT’

OLD STRING
s.text(3) = ‘ZONE T=”PhotoStudio Data” K = 169 F=PAINT’
For REPLACING THE STRING, suppose if I assign
s.text(3) = ‘ZONE T=”PhotoStudio Data” K = 13 L =13 F=PAINT’
it is not assigning so and what is the problem in it?